3 years ago

Please find the square root of 64.

Mathematics

1 answer:

Alexeev081 [22]3 years ago

7 0

You have r^2 = 64 and want to find the square root of 64, which we'll call r.

√(r^2) = r = plus or minus √64

or: r = plus or minus 8

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3 years ago

OM , ON and OP are the angle bisectors of ∠AOB, ∠BOC, and ∠COD respectively. ∠AOD and ∠BOE are straight angles.

Orlov [11]

Find m∠BOC, if m∠MOP = 110°.

Answer:

m∠BOC= 40 degrees

Step-by-step explanation:

A diagram has been drawn and attached below.

OM bisects AOB into angles x and x respectively
ON bisects ∠BOC into angles y and y respectively
OP bisects ∠COD into angles z and z respectively.

Since ∠AOD is a straight line

x+x+y+y+z+z=180 degrees

$2x+2y+2z=180^\circ$

We are given that:

m∠MOP = 110°.

From the diagram

∠MOP=x+2y+z

Therefore:

x+2y+z=110°.

Solving simultaneously by subtraction

$2x+2y+2z=180^\circ$

x+2y+z=110°.

We obtain:

x+z=70°

Since we are required to find ∠BOC

∠BOC=2y

Therefore from x+2y+z=110° (since x+z=70°)

70+2y=110

2y=110-70

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Therefore:

m∠BOC= 40 degrees

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$\frac{y_{2}- y_{1} }{x_{2}- x_{1} }$

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Now we have to,

find the required value of x.

Let's begin,

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