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Hoochie [10]
3 years ago
10

a standard deck of playing cards has 52 cards : 13 spades, 13 clubs, 13 hearts, & 13 diamonds. what is the probability of dr

awing a spade from a 52-card deck, replacing it, & then drawing another spade ??
Mathematics
2 answers:
Fudgin [204]3 years ago
8 0

Answer:

The probability of drawing a spade from a 52-card deck, replacing it, & then drawing another spade is \frac{1}{16}          

Step-by-step explanation:

Given : A standard deck of playing cards has 52 cards : 13 spades, 13 clubs, 13 hearts, & 13 diamonds.

To find : What is the probability of drawing a spade from a 52-card deck, replacing it, & then drawing another spade ?

Solution :

Total number of cards = 52 cards

Number of spade cards = 13 cards

Probability of getting a spade card is \frac{13}{52}

Now, The card we draw replace it.

So, Number of spade card is still = 13

Probability of getting another spade card is \frac{13}{52}

Now, The probability of drawing a spade from a 52-card deck, replacing it, & then drawing another spade is

P=\frac{13}{52}\times\frac{13}{52}

P=\frac{1}{4}\times\frac{1}{4}

P=\frac{1}{16}

Therefore, The probability of drawing a spade from a 52-card deck, replacing it, & then drawing another spade is \frac{1}{16}

8090 [49]3 years ago
5 0

Hi There!

Probability of choosing one suit: 13/52

Choosing 1 spade: 13/52

Putting it aside and choosing another spade: 12/51

Hope This Helps :)

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<u>Answer-</u>

f(2)= 6x^4-10x^3+40x-50=46

<u>Solution-</u>

The given function is,

\Rightarrow f(x)= 6x^4-10x^3+40x-50

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

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\Rightarrow f(2)= 96-50

\Rightarrow f(2)= 46

Therefore, f(2) was found to be 46.


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<h3>Answer:  d.  (4,3)</h3>

========================================================

Explanation:

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It might help to refer to the diagram below.

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