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cupoosta [38]
3 years ago
5

Find the total balance of each investment account earning simple annual interest.

Mathematics
2 answers:
777dan777 [17]3 years ago
8 0
Bruuuuuhhh moment?!!

Crazy boy [7]3 years ago
7 0

Answer:

If my memory for this is correct, the answer should be:

1. 717.60

2. 9311.20

3. 1067.40

4. 380.60

Step-by-step explanation:

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She has 12 apples. She sold 10 and made a $1 profit. How much did she sell each of the 10 apples for?
Papessa [141]

Answer:

0.10 each. just do 1 divided by 10

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Lisa studies 2
olasank [31]
She would have to study about 48 hours to get a score of 97. 
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Solve this problem using the Distributive Property.<br><br> 2 ( 7 + 8 ) =
maria [59]

Answer:

30

Step-by-step explanation:

Original Equation: 2(7 + 8)

So you have to multiply 2 by 7 which equals 14

Then you multiply 2 by 8 which equals 16

Your equation should now look like this: 14 + 16

Add 14 and 16 together.

Your answer is 30

Hope I helped :)

Please condsider brainliest

7 0
3 years ago
Write a sentence representing the equation x+56/7=11
Anastasy [175]
Hey there! :D

x+56/7=11

A number plus fifty-six sevenths is equal to eleven. 

I hope this helps!
~kaikers
8 0
3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
3 years ago
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