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alexandr1967 [171]
3 years ago
5

I need help with my math homework. Find the slope of each line. Thanks!

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
7 is infinite 6 is 4/3 5 is zero 4 is negative 5/4
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I want a skater bf. so i can skate w him smh
Nookie1986 [14]

Answer: um 86%

Step-by-step explanation:

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4 years ago
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The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia
KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = \frac{z-70}{4} . We have

0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

Download pdf
8 0
3 years ago
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting
laiz [17]

Answer: The maximum error = $105.76.

Step-by-step explanation:

Formula to find the maximum error:

E= z^*\dfrac{\sigma}{\sqrt{n}}

, where n= sample size.

\sigma = Population standard deviation

z*= Critical value(two-tailed).

As per given  , we have

\overline{x}=1438

n= 35

\sigma=269

For 98% confidence  , the significance level = 1-0.98=0.02

By z-table , the critical value (two -tailed) =z^* = z_{\alpha/2}=z_{0.01}=2.326

Now , the maximum error = E= (2.326)\dfrac{269}{\sqrt{35}}

E= (2.326)\dfrac{269}{5.9160797831}

E= (2.326)\times45.4692989044=105.761589252\pprox105.76

Hence, With 98% confidence level , the maximum error = $105.76.

4 0
3 years ago
How do u do this?? Number 28
Ede4ka [16]
U just write it in word form

4 0
3 years ago
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