(A+b)(a+b)
I dont understand the writing. I’m doing this math using factoring
X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
The radius of the circle exists approximately 4.95 feet.
<h3>How to estimate the radius of the circle?</h3>
Given the area of the square as A = 98 ft²
The side length of the square choice is equivalent to the diameter of the circle.
First, we must obtain the length of the square.
Area of a square 
98 = L²
L = √98
L = 9.89 ft
Thus the diameter of the circle exists at 9.89 ft
radius = diameter/2
radius = 9.89/2
radius ≈ 4.95 feet
Therefore the radius of the circle exists approximately 4.95 feet.
To learn more about the radius of circle refer to:
brainly.com/question/19568457
#SPJ9
Answer:
its A
Step-by-step explanation:
Hope it helps