Ask question

Ask question

All categories

3 years ago

6

A pole casts a 70-foot shadow. At the same time, a 3-foot mailbox near the pole casts a shadow 3 feet 6 inches. Find the height

of the pole in feet.

2 answers:

ollegr [7]3 years ago

6 0

Answer:

60 ft

Step-by-step explanation:

This can be solved by setting up a proportion.

height of the pole/length of the pole's shadow = height of the mailbox/length of the mailbox's shadow

height of the pole = x

plugging in values

x/70 = 3/3.5 To solve, cross multiply

(3.5)(x) = (70)(3) Simplify

3.5x = 210 Divide both sides by 3.5

3.5x/3.5 = 210/3.5

x = 60 ft is the height of the pole

Degger [83]3 years ago

6 0

60 ft because

This can be solved by setting up a proportion.

You might be interested in

Problem 1: Write each expression in the form a^b, without using any radicals.

VARVARA [1.3K]

By radical do you mean the square root symbol?

7 0

2 years ago

-3a+2b=-3<br> solve for a

vivado [14]

-3a=-3-2b
a=1+2/3b

Solution
a=1+2/3b

7 0

2 years ago

Read 2 more answers

Miranda opened a checking account with $560 from her summer job. She

MaRussiya [10]

Answer:

69 :D

Step-by-step explanation:

its a funny number :v

6 0

3 years ago

Three cube-shaped boxes are stacked one above the other. The volumes of two of the boxes are 1,331 cubic meters each, and the vo

MAVERICK [17]

B.29. that's the answer

8 0

2 years ago

Read 2 more answers

If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).

svetoff [14.1K]

Given:

$f(1)=10$ and $f(n)=f(n-1)-4$ .

To find:

The value of f(5).

Solution:

We have,

$f(n)=f(n-1)-4$

For $n=2$ ,

$f(2)=f(2-1)-4$

$f(2)=f(1)-4$

$f(2)=10-4$

$f(2)=6$

For $n=3$ ,

$f(3)=f(3-1)-4$

$f(3)=f(2)-4$

$f(3)=6-4$

$f(3)=2$

For $n=4$ ,

$f(4)=f(4-1)-4$

$f(4)=f(3)-4$

$f(4)=2-4$

$f(4)=-2$

For $n=5$ ,

$f(5)=f(5-1)-4$

$f(5)=f(4)-4$

$f(5)=-2-4$

$f(5)=-6$

Therefore, the value of $f(5)$ is $-6$ .

5 0

3 years ago