The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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In order to factor this, we will need to take something out to get it to factor. Lets take out a greatest common factor, in this case our greatest common factor will be 3.
We will then write it as:
-3(5t+2)
Answer:
-7, -4
Step-by-step explanation:
The squares are marked by units of 2. It looks like you did not take that into account when you entered your y coordinate.
Answer:
Step-by-step explanation:
Let the numbers be x and y.
<u>The equations are:</u>
<u>Add up the equations to eliminate y and solve for x:</u>
- x - y + 2x + y = 2 + 13
- 3x = 15
- x = 15/3
- x = 5
<u>Now find the value of y:</u>
- y = x - 2
- y = 5 - 2
- y = 3
Answer:
v > 4 is simplified expression.
Step-by-step explanation:
Given that:
v + 5 > 9
This expression says that when 5 is added to a variable v it will be greater than 9 So we will simplify it to get the value for variable v:
Subtracting 5 from both sides:
v + 5 - 5 > 9 - 5
v > 4
This is the simplified expression for given question.
i hope it will help you!
