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sashaice [31]
3 years ago
14

PLZ HELP!!!!!!!!!!!!

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0
P = 2l + 2w
48 = 2(14) + 2w
48 = 28 + 2w

Therefore you could use the equation A.) 2n + 28 = 48, to find the value of N.
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BRAINLIEST + 25 POINTS! ASAP
puteri [66]

y-y1=m(x-x1)

y=40/9(x+4)+20

5 0
3 years ago
Please answer CORRECTLY !!!!!! WILL MARK BRAINLIEST !!!
Feliz [49]

Answer:

5m

and

-8n

Step-by-step explanation:

7m - 2m = 5m

and

-5n - 3n = -8n

Have a great day

7 0
3 years ago
Given a container that is 4.50 ft. by 7.20 ft. that is filled with water 5.00 inches deep.What is the volume of water in liters
elena55 [62]

Answer:

382.3 liters

Step-by-step explanation:

We are told in the question that:

A container that is 4.50 ft. by 7.20 ft. that is filled with water 5.00 inches deep.

This means:

Length = 4.50 ft

Width = 7.20 ft

Depth(Height) = 5.00 inches

We have to convert all of these to centimeters first. Then to liters

1 foot = 30.48 centimetres

1 inch = 2.54 centimetres

Length = 4.50 ft

1 foot = 30.48 centimetres

4.5 ft = 4.5 × 30.48

= 137.16 cm

Width = 7.20 ft

1 foot = 30.48 centimetres

7.20 ft = 7.20 × 30.48 cm

= 219.456cm

Depth(Height) = 5.00 inches

1 inch = 2.54 centimetres

5 inches = x cm

Cross Multiply

= 5 × 2.54 cm

= 12.7 cm

The volume of the water(cm³) = Length × Width × Depth

= (137.16 × 219.456 × 12.7)cm³

382277.428992 cm³

The volume of water in liters

1 cubic centimetre = 0.001 litre

382277.428992 cm³ = x

Cross Multiply

382277.428992 cm³ × 0.001 litre

= 382.2774289920001 liters

Approximately = 382.3 liters

7 0
3 years ago
2/3+q=1/2 what is Q
JulsSmile [24]

Q=rational number=1/6

2/3+q=1/2=1/6

4 0
3 years ago
Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2
Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

<u>Given quadratic equation</u>:

5x^2-6x-2=0

<u>Define the variables</u>:

  • a = 5
  • b = -6
  • c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}

\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}

\implies x=\dfrac{6 \pm \sqrt{76}}{10}

\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}

\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}

\implies x=\dfrac{6 \pm2\sqrt{19}}{10}

\implies x=\dfrac{3 \pm \sqrt{19}}{5}

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}

Learn more about the quadratic formula here:

brainly.com/question/28105589

brainly.com/question/27953354

3 0
1 year ago
Read 2 more answers
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