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1 answer:
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Given:
M=(x1, y1)=(-2,-1),
N=(x2, y2)=(3,1),
M'=(x3, y3)= (0,2),
N'=(x4, y4)=(5, 4).
We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.
For a parallelogram, opposite sides are equal
If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.
To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,
Slope of MN= Slope of M'N'.
Slope of MM'=NN'.
Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'
Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.
Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.
Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.
Answer:
The probability that randomly selected road will be at least 25.8 cm long will be 48%.
Step-by-step explanation:
Given: uniform distribution with min and max values of 18 and 33 respectively.
To find : probability density for upper cumulative frequency i.e 25.8 at least means x25.8 upto 33 cm i.e the maximum limit of function.
Solution:
we have by definition , of uniform distribution
we get , probability density function defines as :
<em>F(x,a,b)= </em><em> </em>
=1/(33-18)=1/15=0.0667.
this is probability density function.
here the x=25.8 , a=18 and b=33
for lower cumulative frequency it defines as ;
P(x,a,b)= =25.8-18/33-18=0.52
for upper cumulative frequency it defines as ;
Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48
here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency
i.e. Q(x,a,b)=0.48
The probability that randomly selected road will be at least 25.8 cm long will be 48%.
Answer: ≈ 196.53 m²
All work is shown in the picture.
