Answer:
Step-by-step explanation:
hello :
note :
Use the point-slope formula.
y - y_1 = m(x - x_1) when : x_1= -4 y_1= 0
m= +5/4 (parallel means same slope)
an equation in the point-slope form is : y +0= -5/4(x+4)
Answer:
24 pounds
Step-by-step explanation:
Step 1: Find out how many pens he bought
12 pens per pack
Charles bought 60 packs
60 packs x 12 pens = 720 pens
Step 2: Find out how much Charles spent
2.80 per pack
Charles bought 60 packs
60 x 2.80 = 168 pounds
Step 3: Find out how many pens Charles sold
Charles sold 2/3 of his pens
2/3 x 720 = 480
Step 4: Find out how manypens he sold
Charles sold the pens for 40p
40p x 480 = 19200p
Step 5: Convert pences to pounds
19200p = 192 pounds
Step 6: Find the profit
192 - 168 = 24 pounds
Step 7: Therefore statement
Therefore he mad 24 pounds of profit
Answer:
A) y = (x + 3)² + 4
B) y = (x - 3)² + 2
C) y = (x - 1)² - 5
Step-by-step explanation:
2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)
As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to
"+ 4" to shift the curve upward by 2
y = (x + 3)² + 4
When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)
This means that the term in parenthesis must be zero with our desired x value
(3 + C)² = 0
3 + C = 0
C = -3
y = (x - 3)² + 2
4 units right and 7 units down mean that the vertex is desired at (1, -5)
(1 + C)² = 0
C = -1
y = (x - 1)² - 5
Answer:
and 
Step-by-step explanation:
Assume that the terminal side of thetaθ passes through the point (−12,5).
In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.
Using Pythagoras theorem:




Taking square root on both sides.

In a right angled triangle




In second quadrant only sine and cosecant are positive.
and 