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Monica [59]
3 years ago
15

What is n in the equation 12 + 12n = -48

Mathematics
1 answer:
Liula [17]3 years ago
3 0
Hello!

To solve an algebraic equation, you must isolate the variable on one side. We’ll begin by restating the given equation:

12 + 12n = -48

Now subtract 12 from both sides of the equation:

12n = -60

Divide both sides by 12:

n = -5

We have now proven that “n” is equal to (-5).

I hope this helps!
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Answer:

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Step-by-step explanation:

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5 0
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X^2 - 8x + 5 = 0
PtichkaEL [24]
<h2>Answer:</h2>

√44

2 Real Roots

<h2>Step-by-step explanation:</h2>

Looking at the image attached, the discriminant is the value under the square root.

In the equation given:

a = 1

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c = 5

The discriminant is therefore:

√(b²- 4ac) = √(-8²- (4*1*5)) = √(64-20) = √44

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8 0
2 years ago
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4 years ago
(3xy/3x^2-12)*(x^2+3x+2/xy+y)
TiliK225 [7]

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<u>Step-by-step explanation:</u>

Here we need to evaluate expression : (3xy/3x^2-12)*(x^2+3x+2/xy+y)  or ,

(3xy/3x^2-12)*(x^2+3x+2/xy+y)

Let's simplify this

⇒ (\frac{3xy}{3x^2-12})(\frac{x^2+3x+2}{xy+y})

Factorizing the terms we get:

⇒ (\frac{3xy}{3(x^2-4)})(\frac{x^2+2x+x+2}{y(x+1)})              { a^2-b^2=(a+b)(a-b)      }

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{x(x+2)+1(x+2)}{y(x+1)})

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{(x+1)(x+2)}{y(x+1)})

Cancelling similar terms we get:

⇒ \frac{x}{x-2}

Therefore , Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

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