The second pair because it would practically be a vertical line.
Answer:
Step-by-step explanation:
2 to the 100 power = 1.2676506002 × 10 to the 30 power.
I'm guessing it is 10? or 7?
Triangle has two solutions: a=4; b=5; c=1.051 and a=4; b=5; c=8.561.
Extra: #1 Obtuse scalene triangle.
Sides: a = 4 b = 5 c = 1.051
Area: T = 0.724
Perimeter: p = 10.051
Semiperimeter: s = 5.026
Angle ∠ A = α = 16° = 0.279 rad
Angle ∠ B = β = 159.846° = 159°50'45″ = 2.79 rad
Angle ∠ C = γ = 4.154° = 4°9'15″ = 0.073 rad
Height: ha = 0.362
Height: hb = 0.29
Height: hc = 1.378
Median: ma = 3.009
Median: mb = 1.517
Median: mc = 4.497
Inradius: r = 0.144
Circumradius: R = 7.256
Vertex coordinates: A[1.051; 0] B[0; 0] C[-3.755; 1.378]
Centroid: CG[-0.901; 0.459]
Coordinates of the circumscribed circle: U[0.526; 7.237]
Coordinates of the inscribed circle: I[0.026; 0.144]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 164° = 0.279 rad
∠ B' = β' = 20.154° = 20°9'15″ = 2.79 rad
∠ C' = γ' = 175.846° = 175°50'45″ = 0.073 rad
Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".