So first we want to find how far away they were after one hour.
Assuming they were going at a steady rate:
Since:
320 miles = distance traveled in 2 hours
We can divide both sides by 2 to get:
160 miles = distance traveled in 1 hour.
So we now know that the trains were 160 miles apart after 1 hour.
So we can assign the eastbound train a variable for its speed right now, or just x. And then the westbound train would be x + 18.
So, since the rate is in miles per hour, and they traveled 160 miles in one hour, we can say:
x + x + 18 = 160 miles
Then just solve.
2x + 18 = 160
-18 -18
2x = 142
/2 /2
x = 71
Since x equals the rate of the eastbound train, and we're looking for the westbound train, just add 18 to 71 because the westbound train was going 18 mph faster than the eastbound train.
18 + 71 = 89
So the rate of the westbound train is 89 mph.
Answer:
= 0.8 + -0.4y
Step-by-step explanation:
Simplifying
5x + 2y = 4
Solving
5x + 2y = 4
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2y' to each side of the equation.
5x + 2y + -2y = 4 + -2y
Combine like terms: 2y + -2y = 0
5x + 0 = 4 + -2y
5x = 4 + -2y
Divide each side by '5'.
x = 0.8 + -0.4y
10p^3=1960p
/10. /10
P^3=196
P=5.8
Answer:
8*8 = 64
Step-by-step explanation:
PERFECT SQUARE
Alright my friend so if she ran 1/4 a mile in just 3 minutes then her overall time will be 12 minutes because she still has 3 more to go so basically it'll be 3 x 4 = 12