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a_sh-v [17]
3 years ago
13

The first equation in a system is 5x+2y=-4. Which equation gives a system with no solution.

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

= 0.8 + -0.4y

Step-by-step explanation:

Simplifying

5x + 2y = 4

Solving

5x + 2y = 4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

5x + 2y + -2y = 4 + -2y

Combine like terms: 2y + -2y = 0

5x + 0 = 4 + -2y

5x = 4 + -2y

Divide each side by '5'.

x = 0.8 + -0.4y

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Hope this helps!
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2 years ago
Write an equation in slope-intercept form for the line with slope -1/4 and y-intercept 9
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If t varies as v, and t = 2 4/7 when v =13/14 , find v when t = 2 1/4.
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8 0
3 years ago
Hey, just trying finish up some math before school ends. What's the answer to 3n+2(-2n-1) ? Thanks!
Ksju [112]

Answer:

-n - 2

Step-by-step explanation:

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3 0
3 years ago
NEED HELP ASAP!
ziro4ka [17]
We see it is the y terms squared so it opens left or right

in form
(y-k)^2=4(p)(x-h)
vertex is (h,k)
and p is distance from focus to vertex, also distance from vertex to directix
if p>0, then it opens to the right and dirextix is to the left of vertex
if p<0, then it opens to the left and directix is tothe right of vertex


so
(y-1)^2=4(4)(x-(-3))
vertex is (-3,1)
4>0 so dirextix is to left of vertex
left is in x direction
-3-4=-7
directix is x=-7
4 0
3 years ago
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