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Zina [86]
3 years ago
5

Efectuati! (-1)+2+(-3)+4+(-5)+...+(-19)+20 Ajutati-ma, va rog!

Mathematics
1 answer:
alexira [117]3 years ago
8 0

Answer:10

Step-by-step explanation:

2+4+6+.....+20- (1+3+5+7+...+19)=(2-1)+(4-3)+(6-5)+....+(20-19)=1+1+...+1 ( de 10  ori= 10 times)

=10

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Find the 7th term of the geometric sequence a3 =128,r=-1/4
kenny6666 [7]

Answer:

Step-by-step explanation:

The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1).  We don't yet know a(1).

If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or

128 = a(1)*(1/16)

and so a(1) = 128/16

resulting in the specific formua a(n) = 8(-1/4)^(n - 1)

Now let's find a(7):

a(7) = 8(-1/4)^1 * (-1/4)^(6)

or

a(7) = 8(-1/4)^7

7 0
3 years ago
Help me please i will give branlist<br> 30% off of 90
lapo4ka [179]

Answer:

answer is 27 hope it helps

4 0
2 years ago
Area is 96 length is 4x+8 width is x find x
dimulka [17.4K]

Answer

Step-by-step explanation:

The area would be length times width. x(4x+8) =96

4x^2+8x = 96

4x^2+8x-96=0. We need to factor.

It would be factored to (4x-16)(x+6) = 0

x would be -6 (x+6=0)

or x would be 4 (4x-16=0)

Why would the width be negative?!? So the answer is 4

4 0
2 years ago
- Trapezoid
zhenek [66]

- Trapezoid

The measures of three angles of a quadrilateral are 70, 125, and 89 degrees. Find the measure of the fourth one.

》The measure of the fourth one is 36°.

<h3>HOPE ITS HELP</h3>

4 0
3 years ago
If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

6 0
3 years ago
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