Answer:
Therefore the complete primitive is

Therefore the general solution is

Step-by-step explanation:
Given Differential equation is

<h3>
Method of variation of parameters:</h3>
Let
be a trial solution.

and 
Then the auxiliary equation is






∴The complementary function is 
To find P.I
First we show that
and
are linearly independent solution.
Let
and 
The Wronskian of
and
is 


≠ 0
∴
and
are linearly independent.
Let the particular solution is

Then,

Choose
and
such that
.......(1)
So that


Now
![4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}-5[2v_1(t)e^{2t}+3v_2(t)e^{3t}] +6[v_1e^{2t}+v_2e^{3t}]=2e^t](https://tex.z-dn.net/?f=4v_1%28t%29e%5E%7B2t%7D%2B9v_2%28t%29e%5E%7B3t%7D%2B%202v%27_1%28t%29e%5E%7B2t%7D%2B3v%27_2%28t%29e%5E%7B3t%7D-5%5B2v_1%28t%29e%5E%7B2t%7D%2B3v_2%28t%29e%5E%7B3t%7D%5D%20%2B6%5Bv_1e%5E%7B2t%7D%2Bv_2e%5E%7B3t%7D%5D%3D2e%5Et)
.......(2)
Solving (1) and (2) we get
and 
Hence

and 
Therefore 


Therefore the complete primitive is

<h3>
Undermined coefficients:</h3>
∴The complementary function is 
The particular solution is 
Then,
and 



Therefore the general solution is

I think you are asking me for the change in degrees, so its
89-62=27
Answer:
4
Step-by-step explanation:
![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
64
32 * 2
16*2*2
8*2*2*2
4*2*2*2*2
2*2*2*2*2*2
![\sqrt[3]{2^{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E%7B6%7D%7D)

4
Answer:
C i think sorry if I'm wrong
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