V=(1/3)hpir²
ok, so inscribed
therefor the edge length is the diameter of the cone (the base is on bottom)
so then d=6
d/2=r
6/2=3=r
height
we need pythagoran theorem to find this
if we look at one side and draw the height then we get a right triangle with height is one leg
3 is another
and 9 is hyptonuse
a²+b²=c²
3²+h²=9²
9+h²=81
h²=72
h=6√2
h=6√2
r=3
V=(1/3)(6√2)(pi)(3²)
V=18pi√2 cubic feet
5.2+4.8= 10
So it has to be 20 I think
This is not a function because -2 and 15 are being repeated in the domain and range.
Answer:
53
Step-by-step explanation: