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DiKsa [7]
3 years ago
5

I^89 simplified. Complex number.

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
This problem can be simplified by remembering that since i= \sqrt{-1}, we have i^{4}=(-1)^{2}=1. Then we have i^{89}=i^{88+1}=i^{88}i^{1}=(i^{4})^{22}i=(1)^{22}i=i.
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