Answer:
Yes, we can.
Explanation:
We can combine with the arithmetic and the concatenation operators to provide augmented assignment operations in the programming language Python.
This mean we can abbreviate expressions like n = n + 1
For example:
n += 10 this is equal to n = n + 10
n += "example" this is equal to n = n + "example"
In this example we have
variable = variable operator expression equal to variable operator = expression.
These arguments are often used in Python's loops.
Answer:
The difference between science and technology can be summarized in the following manner:
Science is more or less a study of a particular branch namely, physics, chemistry or biology. ...
Science involves observation and experimentation whereas technology involves invention and production.
Science is all about analysis whereas technology is more concerned about the synthesis of design.
Explanation:
cool
The correct answer is P2P or peer-to-peer servers.
Hope I helped ;)
Incomplete question. I could only infer you are possibly referring to edhesive unit 8 questions. Here are a few sample questions;
1. Where does Python start?
2. To create the body of a function, we ____________ the code.
Answer:
1. Main Section
2. Indent
Explanation:
1. It is a common rule in Python programming language when coding for for it to begin at the first part of the Main Section.
2. Indenting a code involves creating space or jumping a line away from the margin of the text dialogue box, thus the code written there becomes the body of the function.
Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is 
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 2](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%202)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 3](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%203)
![nums[5] = 4](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%204)
![nums[6] = 5](https://tex.z-dn.net/?f=nums%5B6%5D%20%3D%205)
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 3](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%203)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 4](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%204)
![nums[5] = 5](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%205)
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
<em>This is so because of the way the if statement is constructed.</em>