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Mashutka [201]
3 years ago
12

Which best describes the benefits of renting a home? ARenting can cost more upfront. BRenting is less flexible than owning a hom

e. CRenting has a lease that cost money to break. DNone of the above.
Computers and Technology
1 answer:
yulyashka [42]3 years ago
8 0

Renting can be an alternative to many people, especially those in areas where house prices are very expensive. The benefits to renting a home, however, are not mentioned in the given question, making the best answer (D) none of the above.

Some actual benefits that a person can gain are actually flexibility, since renting means that you can easily move from one place to another compared to buying a home, where you require capital and selling the previous home also falls into your responsibility, while rentals are managed by landlords.

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The answer is webex
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4 years ago
Is pseudocode obtained from Algorithm or is Algorithm obtained from pseudocode?
Anuta_ua [19.1K]

Answer:

An algorithm is defined as a well-defined sequence of steps that provides a solution for a given problem, whereas a pseudocode is one of the methods that can be used to represent an algorithm.

hope this gives you at least an idea of the answer:)

8 0
3 years ago
You work administrative assistant in an engineering firm. A co-worker constantly makes fun of the engineers by whispering commen
victus00 [196]

Answer:

<u>BEST</u>

Option 4

<u>WORST</u>

2

Explanation:

Option 4 is the best cus confronting is better than just watching and letting it happen which in option 2 that's the case

4 0
3 years ago
Write a program that reads in 10 numbers from the user and stores them in a 1D array of size 10. Then, write BubbleSort to sort
Diano4ka-milaya [45]

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

               

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

8 0
3 years ago
what field in the ipv4 datagram header can be used to ensure that a packet is forwarded through no more than N headers
andrew-mc [135]

Answer:

Time to Live (or TTL)

Explanation:

This counter field is initially set at some value that is decremented by one each time the packet "hops." When the counter reaches zero the packet is disposed of.

5 0
2 years ago
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