So first we need to find how much road they have built already this week (on Monday and Tuesday).
We are told that Monday they built
mile and on Tuesday they built
mile. So let's add them together. We'll use a denominator of 12, since that is a common factor to both of them. What you do to the bottom of the fraction you must do to the top:
![\frac{2}{3}=\frac{8}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7B8%7D%7B12%7D%20%20%20)
![\frac{1}{4}=\frac{3}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B3%7D%7B12%7D%20%20%20)
So now that we have a common denominator, we can add them together:
![\frac{8}{12}+\frac{3}{12}=\frac{8+3}{12}=\frac{11}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B12%7D%2B%5Cfrac%7B3%7D%7B12%7D%3D%5Cfrac%7B8%2B3%7D%7B12%7D%3D%5Cfrac%7B11%7D%7B12%7D%20%20%20%20%20)
They built
mile of road so far this week. If they need to build 3, we need to subtract
from 3 to find how much remains. Let's get 3 to a number of 12 so we have a common denominator:
![\frac{3}{1}=\frac{36}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B1%7D%3D%5Cfrac%7B36%7D%7B12%7D%20%20%20)
Now let's subtract:
![\frac{36}{12}- \frac{11}{12}= \frac{25}{12}=2\frac{1}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B36%7D%7B12%7D-%20%5Cfrac%7B11%7D%7B12%7D%3D%20%5Cfrac%7B25%7D%7B12%7D%3D2%5Cfrac%7B1%7D%7B12%7D%20%20%20)
So now we know that the amount of road left that they must build this week is
mile.
Answer:
For game ideas, try to make a game that everyone will want to play. Make it fun, challenging, but still beatable, but not too easy. One thing you could do is a trivia game! With lots of different subjects so people can choose what they get questions about. Also, do a lot of research to get the questions! Hope this helped :)
Step-by-step explanation:
Answer: The tin game's surface area 177 inch²
Step-by-step explanation:
Answer:
Step-by-step explanation:
Two points A and B are given
Using two point formula for straight lines we get
![\frac{x+6}{8+6} =\frac{y-4}{9-4} \\5(x+6) = 14(y-4)\\5x+30 = 14y-56\\5x-14y+86 =0](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B6%7D%7B8%2B6%7D%20%3D%5Cfrac%7By-4%7D%7B9-4%7D%20%5C%5C5%28x%2B6%29%20%3D%2014%28y-4%29%5C%5C5x%2B30%20%3D%2014y-56%5C%5C5x-14y%2B86%20%3D0)
b) A line parallel to AB would be of the form
5x-14y +k=0
Since the line passes through (14,-6) substitute to get k
5(14)-14(-6)+k=0 Or k = -154
Line is 5x-14y-154 =0
c) A line perpendicular to AB would have form as
14x+5y =k1
Substitute (-5,-10) to get k
14(-5)+5(-10) =k1
Or k1 = -120
Hence equation is 14x+5y = -120
Answer:5+6m
Step-by-step explanation: