Answer:
You can use the ASA congruence theorem.
Answer:
C. 3
Step-by-step explanation:
Let the larger number be denoted by x.
Let the smaller number be denoted by y.
Given the following parameters;
............equation 1
.........equation 2
From equation 1;
.........equation 3
Substituting equation 3 into equation 2, we have;
![3(5+y) + 2y = 30](https://tex.z-dn.net/?f=3%285%2By%29%20%2B%202y%20%3D%2030)
![15 + 3y + 2y = 30](https://tex.z-dn.net/?f=15%20%2B%203y%20%2B%202y%20%3D%2030)
![15 + 5y = 30](https://tex.z-dn.net/?f=15%20%2B%205y%20%3D%2030)
![5y = 30 - 15](https://tex.z-dn.net/?f=5y%20%3D%2030%20-%2015)
5y = 15
Divide both sides by 5;
y = 15/5
y = 3.
Substituting the value of y into equation 3, we have;
x = 5 + 3 = 8.
<em>Therefore, the value of the smaller number is 3 and the larger number is 8.</em>
The answer would be D. 56in^2
Answer: the answer will be that X equals 0 hope this helps
Step-by-step explanation: