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jeka94
4 years ago
6

Rewrite the expression 14m-(5+8m)

Mathematics
1 answer:
DIA [1.3K]4 years ago
8 0

Answer:5+6m


Step-by-step explanation:


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Knowledge, intensify, skills and grow net work​
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4 years ago
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Anybody know the answer?
german
The answer 1 because because 1-cosx^2 =sinx^2 and cotx^2+1=cscx^2 =1/sinx^2 and sinx^2/sinx^2=1
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5 0
3 years ago
you earned a 90% on a science test yoy answer 18 questions correctly how many questions were on the test
Talja [164]
X= entire test
if
18=.9x
then divide both sides by .9
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20 questions total on the test
6 0
4 years ago
Find the values of m and b that make the following function differentiable. the piecewise function f of x equals x cubed when x
aalyn [17]

f(x)=\begin{cases}x^3&\text{for }x\le1\\mx+b&\text{for }x>1\end{cases}

f must be continuous in order to be differentiable, so we need to have

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)

By its definition, f(1)=1^3=1, and

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}x^3=1

\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}(mx+b)=m+b

so that \boxed{m+b=1}.

We want the derivative to exist at x=1, which requires that we pick an appropriate value for f'(1) so that f'(x) is also continuous. At the moment, we know

f'(x)=\begin{cases}3x^2&\text{for }x1\end{cases}{/tex]so we need to pick [tex]f'(1) such that

\displaystyle\lim_{x\to1^-}f'(x)=\lim_{x\to1^+}f'(x)

We have

\displaystyle\lim_{x\to1^-}f'(x)=\lim_{x\to1}3x^2=3

\displaystyle\lim_{x\to1^+}f'(x)=\lim_{x\to1}m=m

so that \boxed{m=3} (which means we need to pick f'(1)=3) and so m+b=1\implies\boxed{b=-2}

5 0
4 years ago
A. Give two examples of addition of Like Fractions.
zavuch27 [327]

Answer:

A: 3/5 + 2/5 = 5/5

A: 3/5 + 1/5 = 4/5

B: 3/5 - 2/5 = 1/5

B: 3/5 - 1/5 = 2/5

C: 3/5 x 2/5 = 6/25

C: 3/5 x 1/5 = 3/25

C: 2/5 x 1/5 = 2/25

D: 1/2 + 1/4 = 3/4

D: 4/5 + 4/10 = 6/5

E: 4/6 ÷ 2/6 = 2

E: 1/6 ÷ 1/6 = 1

Step-by-step explanation:

5 0
3 years ago
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