To solve this problem you must apply the proccedure shown below:
1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
(y^2/a^2)+(x^2/b^2)=1
2. You have the distance from the center of the ellipse to the focus:
c=12, therefore, you can calculate the value of b, the minor radius:
c^2=a^2-b^2
b=√(13^3-12^2)
b=5
3. Therefore, the equation is:
a^2=169
b^2=25
(y^2/169)+(x^2/25)=1
The answer is: (y^2/169)+(x^2/25)=1
Do u have a pic of the problem?
Answer:
<u>The negative solution is -4</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
x = a number
4x = x² - 32 (4 times a number is 32 less than the square of that number)
2. Let's solve for x and find the negative solution:
4x = x² - 32
-x² + 4x + 32 = 0
x² - 4x - 32 = 0 (Multiplying by - 1)
(x - 8) (x + 4) = 0
(x₁ - 8) = 0
(x₂ + 4) = 0
x₁ = 8
<u>x₂ = -4</u>
<u>The negative solution is -4</u>
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Answer:
x ≈ 14.57
Step-by-step explanation:
using the sine ratio in the right triangle
sin59° = 
= 
( multiply both sides by 17 )
17 × sin59° = x , then
x ≈ 14.57 ( to 2 dec. places )
