The 4 subintervals are given: [2, 4], [4, 7], [7, 9], and [9, 10].
Each subinterval has length: 4 - 2 = 2, 7 - 4 = 3, 9 - 7 = 2, and 10 - 9 = 1.
Over each subinterval, we take the value of the function at the right endpoint: 3, 8, 15, and 18.
Then the integral is approximately
so 78.0 is the correct answer.
Answer:
On average, students in the 4th period did more chin-ups than students in the 2nd period
Step-by-step explanation:
Given the table values as
2nd Period 3 4 12 14 7 7 8 4 8 3 11 10 9 8 10 4 8 7 13 9
4th Period 10 3 14 14 16 15 7 12 7 10 12 8 10 9 6 11 9 1 2 5
Find the average chin-ups done by students in the gym classes
For 2nd Period gym class, the average will be;
=sum of chin-ups ÷ number of students
=sum of chin-ups in 2nd period gym class=
=number of students=20
Average=159÷20
=
For 4th Period gym class
Sum of chin-ups=
Number of students=20
Average number of chin-ups in the 4th period gym class
Average number of chin-ups in 2nd Period Class = 8
Average number of chin-ups in 4th Period Class= 9
Conclusion; On average students in the 4th period gym class made more chin-ups (9) than those in 2nd period gym class (8).
Reason:
When rotating a point 180 degrees around the origin, you use the rule
We flip the sign of each coordinate from positive to negative or vice versa.
The point X is at the location (-4, 1). Rotating this 180 degrees will get us to X'(4, -1)
