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brilliants [131]
3 years ago
11

23) A shopkeeper buys 1 dozen of pens at Rs. 20 each and sells at Rs. 18 each. Find his loss and loss percent. 24) The marl​

Mathematics
2 answers:
kramer3 years ago
6 0

Answer:

loss = 24, loss % = 10

Step-by-step explanation:

amount he spent = 12*20 = 240

amount he earnt = 12*18 =216

loss = 240-216 = 24

loss % = 24/240 x 100% = 10%

GaryK [48]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Find the area of the semicircle.
PSYCHO15rus [73]
So we know that the area of a full circle is pi multiplied by radius squared
But for a semicircle the area is pi multiplied by radius squared divided by two
So, we do 3.14*3^2/2
Which is 14.13
6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!! WILL GIVE BRAINLIEST
Katyanochek1 [597]

Answer:

equilateral triangle

Step-by-step explanation:

EQUILATERAL ... all three sides are equal length

ISOSCELES ... two sides are equal length

SCALENE ... none of the three sides are equal length

RIGHT ... one of the angles measures 90 degrees

OBTUSE ... one of the angles measures greater than 90 degrees

ACUTE ... all three angles measure less than 90 degrees

4 0
2 years ago
A movie theater has a seating capacity of 289. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
torisob [31]

Answer:

Number of children in theater   = 94

Number of students   = 46

Number of adults in theater= 47

Step-by-step explanation:

Total seating capacity in the theater = 187

Let us assume the number of students in the theater = m

and assume  the number of children in the theater = 2k

So, the number of adults in theater = Half of number of children = 2k/2 = k

⇒ Number of ( Adults + Children + students) = 187

⇒ k  + 2k + m =  187, or 3k + m = 187

Step-by-step explanation:

4 0
3 years ago
Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou
mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

\frac{dQ}{dt} = -kQ

In which k is the decay rate.

The solution is:

Q(t) = Q(0)e^{-kt}

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that Q(0) = 8000

500 counts per minute 13 days later.

This means that Q(13) = 500. We use this to find k.

Q(t) = Q(0)e^{-kt}

500 = 8000e^{-13k}

e^{-13k} = \frac{500}{8000}

\ln{e^{-13k}} = \ln{\frac{500}{8000}}

-13k = \ln{\frac{500}{8000}}

k = -\frac{\ln{\frac{500}{8000}}}{13}

k = 0.2133

So

Q(t) = Q(0)e^{-0.2133t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.2133t}

0.5Q(0) = Q(0)e^{-0.2133t}

e^{-0.2133t} = 0.5

\ln{e^{-0.2133t}} = \ln{0.5}

-0.2133t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.2133}

t = 3.25

The half-life of the radioactive substance is of 3.25 days.

7 0
3 years ago
K/5.2+81.9=47.2<br> please show work tysm
grin007 [14]

Answer:

/5.2 + 81.9 = 47.2

Step-by-step explanation:

Subtract 81.9  from both sides of the equation

Simplify

Subtract the numbers

Multiply all terms by the same value to eliminate denominators

Cancel multiplied terms that are in the denominator

Multiply the numbers

Solution: k = -180.44

3 0
3 years ago
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