You mean Y=x^2 + 4x + 4, this is quadratic function (convex parabola) which standard form is y=ax^2+bx+c
1. First we will find zero of the function, y=0 or as you like intersection with x axis. y=0 =>. x^2+4x+4=0 => this is the square of the binomial ( x + 2)^2 = 0 => x + 2 = 0 => x= -2 In this case it's a touch point with x axis. 2. Intersection with y axis => If x=0 => y=4 (0, 4) 3. The coordinate of vertex are x= - b/2a = - 4/2 = -2 and y=(4ac-b^2)/4a y= (4* 1*4 - 4^2)/ 4 = (16-16)/4= 0 Vmin ( -2, 0) this point is at same time zero of the function. 4. Domain:. Dx=R (field of real numbers) 5. Range: y belong to interval ( - infinite, 0) or R- 6. Function's sign y>0 => x belong to intervals (-infinite, -2) U ( -2, +infinite) 7. Function's growth or decline for x belong interval ( -infinite, -2) => function decline for x belong interval ( -2, +infinite) => function is growing
