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2 years ago

In the scale drawing, what will the length of the east, south, west, and north side of the backyard be?

Mathematics

2 answers:

Y_Kistochka [10]2 years ago

7 0

Answer:

One cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

Step-by-step explanation:

Len [333]2 years ago

3 0

Hi can I have a shout out please thank you for the help I have to help with the

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What are the rectangular coordinates of the polar coordinates <img src="https://tex.z-dn.net/?f=%282%5Csqrt%7B2%7D%20%2C-%5Cfrac

melamori03 [73]

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3 years ago

Read 2 more answers

72 percent of 350 friends

lana [24]

We have an equation: ?/350= 72/100

Cross multiply:
100*?= 72*350
⇒ ?= 72*350/100= 252

72% of 350 friends is 252 friends~

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3 years ago

Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C

netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

 $|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}$

Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.

$|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5$

$|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6$

$|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4$

$|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \ \sqrt{25}=5$

$|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4$

Answer: B and D

3 0

3 years ago

Dan bought one package if blackberries for 3 dollars/euros. How many packages can Darryl buy if he has 15 dollars/euros?

myrzilka [38]

Answer:

Dan can buy 5 bags for 15 dollars

Step-by-step explanation:

divide 15 and 3 it will equal 5

6 0

2 years ago

Read 2 more answers

Two cells are viewed and measured under a microscope. The approximate diameter

nikklg [1K]

Answer:

option D. 4.7 x 10-4 m

Step-by-step explanation:

The correct question is

• cell P: 5.0 x 10-4 meters

• cell Q: 3.0 x 10-5 meters

we have

The diameter of cell P is $5*10^{-4}\ m$

The diameter of cell Q is $3*10^{-5}\ m$

Rewrite the diameter of cell P as

$5*10^{-4}\ m=5*10^{-4}(\frac{10}{10})=50*10^{-5}\ m$

Find the difference

$50*10^{-5}\ m-3*10^{-5}\ m=47*10^{-5}\ m$

Rewrite the difference as

$47*10^{-5}\ m=47*10^{-5}}(\frac{10}{10})=4.7*10^{-4}\ m$

7 0

3 years ago