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Verizon [17]
3 years ago
6

Find the sum of the measures of exterior angles, one at each vertex, of an octagon.

Mathematics
2 answers:
Aleksandr [31]3 years ago
4 0

Answer:

C. 1080

Step-by-step explanation:

1) Find the measure of one interior angle  

2) From that, find the measure of one exterior angle  

3) Multiply that by 8


hjlf3 years ago
3 0
A rule of polygons is that the sum<span> of the </span>exterior angles<span> always equals 360 degrees, but lets prove this for a regular </span>octagon<span> (8-sides). First we must figure out what </span>each<span>of the interior </span>angles<span> equal. To do this we use the </span>formula<span>: ((n-2)*180)/n where n is the number of sides of the polygon</span>
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\dfrac{-2}{3} \div 2\dfrac{1}{4} = <br> 3<br> −2<br> ​ <br> ÷2 <br> 4<br> 1<br> ​
bekas [8.4K]

Answer:

\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

Step-by-step explanation:

Given

\dfrac{-2}{3} \div 2\dfrac{1}{4} =

Required

Solve

Start by converting the mixed number to improper fraction

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