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gayaneshka [121]

3 years ago

11

A toy has various shaped objects that a child can push through matching holes. The area of the square hole is 8 square centimete

rs. The volume of a cube shaped block is 64 cubic centimeters. Ehich edge length can you find?

1 answer:

Vinil7 [7]3 years ago

6 0

Since, a toy has various shaped objects that a child can push through matching holes.

The area of the square hole is 8 square centimeters and the volume of a cube shaped block is 64 cubic centimeters.

We have to identify the edge length, which we can determine.

Since, an edge is where two faces meet. Since, square is two dimensional figure, it has no faces. Cube is a three dimensional figure with 12 edges.

Since, Volume of cube shaped block = 64 cubic centimeters

$(edge)^3 = 64$

$edge = (64)^\frac{1}{3}$

$edge = (4)^{3 \times \frac{1}{3}}$

So, edge of cube shaped block = 4 cm

Therefore, we can determine the edge of cube shaped block.

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Step-by-step explanation:

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Answer:

A. 32, 85, 89, 91, 92, 92

Step-by-step explanation:

A. 32, 85, 89, 91, 92, 92

Mean

$\bar{x}=\dfrac{32+85+89+91+92+92}{6}\\\Rightarrow \bar{x}=80.167$

Since the number of scores is 6 which is an even number the median will be of the form $\dfrac{x_{n/2}+x_{(n/2)+1}}{2}$

Median

$\dfrac{89+91}{2}=90$

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B. 72, 78, 79, 80, 82, 82

Mean

$\bar{x}=\dfrac{72+78+79+80+82+82}{6}\\\Rightarrow \bar{x}=78.83$

Median

$\dfrac{79+80}{2}=79.5$

Difference of mean and median = $|78.83-79.5|=0.67$

C. 65, 70, 75, 80, 85, 90

Mean

$\bar{x}=\dfrac{65+70+75+80+85+90}{6}\\\Rightarrow \bar{x}=77.5$

Median

$\dfrac{75+80}{2}=77.5$

Difference of mean and median = $|77.5-77.5|=0$

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$\bar{x}=\dfrac{30+34+39+41+48+50}{6}\\\Rightarrow \bar{x}=40.33$

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$\dfrac{39+41}{2}=40$

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So, A has the maximum difference of 9.83 between the mean and the median.

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