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otez555 [7]
3 years ago
8

Francisco’s game involves 3 green, 2 yellow, 4 red, and 3 black marbles.If he randomly draws three marbles from the bag, without

replacement, what is the probability that he will draw yellow, and then red, and the black? HELP
Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer is b

Step-by-step explanation:

I already did it

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The following table shows the number of classes that
Tresset [83]

Answer:

There are 6 classes we find the median by finding the middle number of the 3rd highest class and 4th highest class, even if this is a decimal.

6/3 = 3+ 0.5

The process would be different if some values are the same values already on the chart total of each class.

ie) 20  31  14  22 20 31

small data like this below you can rearrange

14  20  20  22  31 31  

and see that 21 is the correct value

as there are even numbers, so we choose 20 , 22

and select the middle value = 21

Step-by-step explanation:

If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.

7 0
3 years ago
Pls answer 9-12 will give brainliest
Elanso [62]
9. $112.50 / 9 lawns = $12.50 per lawn
10. $122.50 / 7 lawns = $17.50 per lawn
11. $112.50 / 7.5 hours = $15.00 per hour
$122.50 / 5 hours = $24.50 per hour
Alastair earns more per hour
12. Taryn: 49 more hours ($735 / $15.00)
Alastaie: 30 more hours ($735 / $24.50)
You found how much money they charge per hour in 11 so use that to find how many hours it takes to earn $735.
6 0
3 years ago
Javion drank 7/8 quart of juice in two days. He drank 1/4 quart of juice yesterday. How much did he drink today?
o-na [289]

Step-by-step explanation:

7/8 - 1/4 = 5/8

__z_________z_

4 0
3 years ago
Joey invest $900 at 4% simple interest for 2 years but he wants to know how much money he will have after only 18 months. Determ
malfutka [58]
Well, bearing in mind that, a year has 12 months, so 18 months is really just 18/12 of a year, or 3/2 a year, then

\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$900\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to \frac{18}{12}\to &\frac{3}{2}
\end{cases}
\\\\\\
A=900\left( 1+0.04\cdot \frac{3}{2} \right)
4 0
3 years ago
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
3 years ago
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