Answer:
G7. (2√3)/3
G8. -2+√7
G9. (6 +2√2 -3√3 -√6)/7
Step-by-step explanation:
G7.

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G8.

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G9.

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<em>Comment on the problems</em>
In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).
The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.
Answer:
A and C
Step-by-step explanation:
Unsolvable because there is no factor for 13
Answer: The correct line is

Step-by-step explanation: We are given the following two sets of quadratic expressions in various forms:

We are to select one of the lines from above that represent three equivalent expressions.
We can see that there are three different forms of a quadratic expression in each of the lines:
First one is the simplified form, second is the factorised form and third one is the vertex form.
So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.
We have

and

So,

Thus, Line 1 contains three equivalent expressions.
Now,

and

So,

Thus, Line 2 does not contain three equivalent expressions.
Hence, Line 1 is correct.