A. = logb (3/7)^1/2
= logb 3^1/2 - logb 7^1/2
= 1/2(logb 3 - logb 7)
b. = log 7x^3 + log y^5
= log 7 + log x^3 + log y^5
= log 7 + 3 log x + 5 log y
Answer:
Consider the expression
. q is called the quotient, a is is the dividend and b is the divisor.
Since q is a multiple of 6, then q has the form
for some integer k.
Since a is a multiple of 9, then a has the form
for some integer s.
Since b is a factor of 12, then if 12 can be expressed of the form
, for c an integer. Then b has the form 
Replacing the preview expression in the initial expression we obtain:

Then
is a equation to Isabel's problem.
Answer:17 x 7= y x 2
Step-by-step explanation: