2 real roots and 2 imaginary roots
f(x) = (x - 3)(x + 3 )(x-2 + i)(x - 2 - i)
(x - 3) and (x + 3) give real roots x = ± 3
(x - 2 + i)(x - 2 - i) give 2 imaginary roots x = 2 ± i
The vertex point would be (1,3)
explanation:
-b/2a:
-(-2)/2(1)
2/2=1
Plug 1 in for all the X’s
y=1^2-2(1)+4
y=3
I’m here to help.
For this question here you need to use the sine formula for the area of a triangle and figure out the area of the sector
I’ll take you through it step-by-step
Area of the arc:
We only have 68.9 degrees out of 360 and we need to use the formula for the area of a circle.
Formula of a circle = pi x radius squared
68.9/360 x pi x 86.1184= 51.78 (2dp)
Area of triangle:
As you can see we have no height so we must use the sine formula for the area of a triangle.
Formula= 1/2abSinC
You should end up with
0.5 x 9.28x 9.28 x Sin(68.9)= 40.17 (2dp)
Now since you want the area of the segment shaded, just find the difference between these two values.
51.78-40.17 = 11.61
Answer= 11.6cm squared
Hope this helped!
If every inch is 200 miles just do 200 times 7 to get the answer of 1400 miles
