PLS HELP I need to know is this right?
2 answers:
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Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:
AC = 6
Step-by-step explanation:
y is the dimension of the horizontal segment (see the attached image).
The hypotenuses are the same dimension, so:
(x+4)^2=(x/2)^2+y^2
(3x-8)^2=(x/2)^2+y^2
So,
(x+4)^2 = (3x-8)^2
x+4 = 3x-8
x-3x = -8-4
-2x = -12
x = 6
And x is the dimension of the segment AC.
Hi!
<h3>To find the slope, use this formula</h3>Hope this helps! :)
-Peredhel