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3 years ago

What is scale factor of the two triangles ?

Mathematics

2 answers:

Arada [10]3 years ago

6 0

Answer:

GKN is 3/4 of AHL

Step-by-step explanation:

Compare the similar sides. 3:4. 6:8. 15:20. All of them are equivalent to 3/4

GenaCL600 [577]3 years ago

4 0

Answer:

A. 3/4

Step-by-step explanation:

We have to find which sides correspond to which other ones'.

The sides in order of increasing in triangle 1: NK, GK, GN

The sides in order of increasing in triangle 2: AH, HL, AL

AH~NK 4 ~ 3

HL~GK 8 ~ 6

AL~GN 15 ~ 20

When we put them into a fraction and simplify that should be our answer.

$\frac{3}{4}$ = $\frac{6}{8}$ = $\frac{15}{20}$

The simplest fraction is 3/4 so that is our answer.

If you want to make ΔAHL = ΔNKG you have to multiply each of the sides by 3/4. But if you want to make ΔNKG = ΔAHL multiply each side of ΔNKG by 4/3.

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for what values of A does the acute angle formed by the lines 3x+2y=10 and Ax-2y=3 have measure of 45 degree

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Answer:

Step-by-step explanation:

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2 years ago

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garik1379 [7]

Answer:

Step-by-step explanation:

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2 years ago

Suppose you are given a cube made of magnesium (mg) metal of edge length 2.15 cm. (a) calculate the number of mg atoms in the cu

SVETLANKA909090 [29]

solution:

a) To calculate the volume of cube of edge 1.0cm

Volume= (edge)³

=(100cm) ³

= 1cm³

To find the mass of MG atoms

Density = mass/volume

Mass of mg = 1.74g/cm³ x 1cm³

= 1.74g

To find the number of mg atoms,

Molar mass of mg = 24.31g

24.31g mg contain 6.022 x 10²³ atoms of mg

1.74g mg contain = 6.022 x 10²³mg atoms/24.31g mg x 1.74g mg

= 0.4310 x 10²³mg atoms

= 4.31 x 10²² mg atoms

B) to find the volume occupied by mg atoms

Total volume of cube = 1 cm³

Volume occupied by mg atoms

= 74% of 1cm³

=74/100 x 1cm³= 0.74cm³

To find the volume of 1 mg atom

4.31 x 10²² mg atoms occupy 0.74 cm³

1 atom will occupy 0.74cm³

1 atom will occupy = 0.74cm³/4.31 x 10²²mg atoms x 1mg atom

volume of 1 mg atom = 0.1716 x 10⁻²²cm²

Volume of 1 mg atom = 4/3 π³ in the form of sphere.

4/3πr³ = 0.1716 x 10⁻²²cm³

R³ = 0.1716 x 10⁻²²cm³x 4/3 x 7/22

R³ = 0.04095 x 10⁻²²cm³

R = 0.1599 x 10⁻⁷cm

1 = 10⁻¹⁰cm

= 0.1599 x 10⁻⁷cm

= 1pm/1 x 10⁻¹⁰cm x 0.1599 x 10-7cm

= 1.599 x 10² pm

R= 1.6 x 10²pm

3 0

2 years ago

The interior angles formed by the sides of a pentagon have measures that sum to 540°. What is the measure of angle B?

patriot [66]

Answer:

m∠B = 110°

Step-by-step explanation:

We know that,

The sum of the measures of the angles in a pentagon is 540°.

So, we get,

130 + (x-5) + (x+30) + 75 + (x-35) = 540

i.e. 3x + (130+30+75) - (5+35) = 540

i.e. 3x + 235 - 40 = 540

i.e. 3x + 195 = 540

i.e. 3x = 540 - 195

i.e. 3x = 345

i.e. x= 115°

Now, as m∠B = (x-5)° = (115-5)° = 110°

Hence, the measure of angle B is 110°.

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Answer:

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