Answer:
my mom it crack at the tame
Step-by-step explanation:
I I I yu hfugy7 jvc cdfbjdyng65yygdgggghnhghgfgvvgfvggvb cccghb
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So
has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
<span>the product of a number and the same number less 3
x(x – 3)</span>
The words "the product of" tell us we're going to multiply a number times the number less 3. In this case, we'll use parentheses to represent the multiplication. The words "less 3" tell us to subtract three from the unknown number.
a number divided by the same number less five
The words "divided by" tell us we're going to divide a number by the difference of the number and 5. In this case, we'll use a fraction to represent the division. The words "less 5" tell us we need a minus sign because we're going to subtract five.
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The first one I THINK is 21 and the second one I THINK is 20. I'm not sure though sorry if I'm wrong
Answer: 7cm
Step-by-step explanation:
Use pythagorean theorum:
Variables:
Let the edge = A
Face diagonal (F) = 10cm
Inner diagonal (I) = sqrt(150) cm
A^2 = I^2 - F^2
A^2 = [sqrt(150)]^2 - 10^2
A^2 = 150 - 100
A^2 = 50
A = sqrt(50)
A = 7.0710678 cm
A = 7cm (to the nearest tenth)
so, length of an edge = 7cm
