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Hunter-Best [27]
3 years ago
15

Help help help! I need theses answers QUICK

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0
I can give you answers to 1, 2, and 5.

1 is a
2 is b

5 looks like parallel lines
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Find a number x such that g(x) = -4
mel-nik [20]

Answer:

C: x = 7

Step-by-step explanation:

The easiest way to do this is to simply try all of the x-vales given as options.

Option 1: x = -1

Since -1 \leq 0, we'll use the first equation.

g(x)=\mid x \mid - 2\\g(-1)=\mid -1 \mid - 2 = 1 - 2 = -1

As we can see, g(-1) is not -4.

Option 2: x = 3

Since 0 < 3 < 4, we'll use the 2nd equation.

g(x) = x-3\\g(3) = 3-3 = 0

Not -4.

Option 3: x = 7

Since 4 \leq 7, we'll use the 3rd equation.

g(x) = 3-x\\g(7) = 3-7 = -4

Tada! We have found a number such that g(x) = -4, it is 7. Since we only need to find a number, not all numbers, we don't have to check the last option. However, if you're curious:

Option 4: x = 4

Since 4 \leq 4 (less than <em>or equal to</em>), we'll use the 3rd equation.

g(x) = 3-x\\g(4) = 3-4 = -1

3 0
3 years ago
What’s the answer I just need a quick answer and my teacher thinks I’m wrong
Goryan [66]

Answer:

58.5

Step-by-step explanation:

9 x 13 = 117

117 divided by 2 = 58.5

3 0
3 years ago
Find a numerical value of one trigonometric function of x for cscx=sinxtanx+cosx
ehidna [41]

cscx = sinx tan x + cos x

Using xsx x = 1/sin x and tan x = sin x/cos x

\frac{1}{sin x} = sinx *\frac{sinx }{cos x} + cosx

\frac{1}{sin x} = \frac{sin^2x +cos^2x}{cos x}

\frac{1}{sin x} = \frac{1}{cos x}

Multiplying both sides by cos x

\frac{cos x}{sin x} = 1

cot x =1

Correct option is d .

5 0
3 years ago
Read 2 more answers
Solve those attachments for 100 points
andrew-mc [135]

Please don't delete this, I think I will be able to help! I just need to see the image.

8 0
3 years ago
Read 2 more answers
I need help to solve this question.
LekaFEV [45]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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