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IrinaK [193]
3 years ago
14

Pls answer this question quickly.

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0

Below is the pseudocode of the "test" algorithm:

algorithm "test"

var

A: VECTOR [1..3,1..3] OF WHOLE

C, L, M: WHOLE

start

RANDOM 1,50

FOR L OF 1 ATE 3 KNIFE

FOR C OF 1 ATE 3 KNIFE

READ (A [L, C])

SE (L = 1) E (C = 1) ENTAO

M <-A [L, C]

END IF

IF A [L, C]> M ENTAO

M <-A [L, C]

END IF

FIMPARA

FIMPARA

WRITING ("**** MATRIX A ****")

FOR L OF 1 ATE 3 KNIFE

FOR C OF 1 ATE 3 KNIFE

WRITE (A [L, C]: 4)

FIMPARA

WRITING

FIMPARA

WRITING (M)

final algorithm

On this algorithm, analyze the following sentences:

I. A is a matrix whose elements are integers generated randomly.

II. A is an order 3 matrix.

III. At the end of its execution, the algorithm prints the smallest value of the matrix.

IV. At the end of its execution, the algorithm prints the largest value of the matrix.

Now, mark the alternative that presents the CORRECT answer.

Alternatives:

The)

Only affirmative III is correct.

B)

Affirmations I and II are correct.

w)

Affirmations I, II and III are correct.

(d)

Affirmations I, II and IV are correct.

and)

All statements are correct.

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Which polynomial represents the sum below (x^8 + 2x^4 + 1) + (2x^4 + x^2 + 1)
Serggg [28]

To add the polynomials \tt {x}^{8}  +  {2x}^{4}  + 1 and \tt {2x}^{4}  +  {x}^{2}  + 1 let us first combine the like and unlike terms and add them :

=\tt  {x}^{8}  +  {2x}^{4}  + 1 + \tt {2x}^{4}  +  {x}^{2}  + 1

= \tt {x}^{2}  +  {x}^{2}   +  {x}^{2} +  {x}^{2}  +  {2x}^{2}  +  {2x}^{2}  +  {2x}^{2}  +  {2x}^{2} +  {x}^{2}  + 1 + 1

=\tt  {13x}^{2}  + 2

<h3>○=> Therefore :</h3>

\color{hotpink} = \tt  {x}^{8}  +  {2x}^{4}  + 1 + \tt {2x}^{4}  +  {x}^{2}  + 1 \color{plum}=  {13x}^{2}  + 2

5 0
2 years ago
Ask Your Teacher Consider a binomial random variable with n = 5 and p = 0.8. Let x be the number of successes in the sample. Eva
Readme [11.4K]

Answer:

0.942 is the required probability.  

Step-by-step explanation:

We are given the following in the question:

x is a binomial random variable with n = 5 and p = 0.8.

Then,

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

We have to evaluate:

P(x \geq 3) = P(x = 3) + P(x = 4) +P(x=5)\\\\= \binom{5}{3}(0.8)^3(1-0.8)^2 +\binom{5}{4}(0.8)^4(1-0.8)^1 +\binom{5}{5}(0.8)^5(1-0.8)^0\\\\= 0.2048 +0.4096+0.3276=0.942

0.942 is the required probability.

4 0
3 years ago
What is the slope between the points (5,-7) and (-7,1)?
SCORPION-xisa [38]
I hope this helps you



(5,-7) x'=5 y'= -7


(-7,1) x"= -7 y"=1


slope. (x'-x")=y'-y"


slope. (5-(-7))= -7-1


slope. 12= -8


slope =-8/12


slope = -2/3
6 0
3 years ago
PLZ HELP ME I NEED HELP
NemiM [27]

Answer:

A,C and B

Step-by-step explanation:

4 0
3 years ago
What are the solutions of 4x^2 -8x+5=0
Ilia_Sergeevich [38]

Answer:

It is no real solutions

Step-by-step explanation:

5 0
2 years ago
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