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3 years ago

9

There are 48 boys in the seventh grade. There are 2 boys for every 1 girl in the seventh grade. How many girls are in the sevent

h grade

1 answer:

ivann1987 [24]3 years ago

5 0

There are 24 girls in the seventh grade

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Mandy bought a desktop computer system to start her business from home for $4,995. It is expected to depreciate at a rate of 10%

ziro4ka [17]

Answer:

8.43 years

Step-by-step explanation:

Given data

Cost price P= $4995

Rate r= 10%

FInal amount A= $2150

The expression for the time/duration is given as

t= ln(A/p)/r

t= ln(2150/4995)/0.1

t= ln(0.430)/0.1

t= 0.843/0.1

t= 8.43

Hence the time it will take is 8.43 years

3 0

3 years ago

I don’t even know where to begin on this one

TiliK225 [7]

Answer:

This is simple linear regression analysis. We can determine the line of best fit using technology

Step-by-step explanation:

5 0

3 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago

50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n

irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0

3 years ago

What is the value of x

il63 [147K]

the 2 angles are congruent so...

x+40=3x set the 2 equations equal to each other

40=2x subtract x from both sides

20=x divide by 2

x=20 is the final answer

Have a blessed day!

5 0

2 years ago

Read 2 more answers