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SashulF [63]
3 years ago
10

Specify the set of all integers that are congruent to 5 (mod 7) using (a) the roster method and (b) set-builder notation

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

(a) A = {... -23, -16, -9, -2, 5, 12, 19, 26, ....}

(b) A = {x\in Z: x = 5 - 7t,\ t\in Z}

Solution:

For two integers x and y to be congruent, we know that:

If 't' divides y - x, we say that x is congruent to y modulo t, written x ≡ y mod t.

Now,

In roster form, we include each element in the representation of the set.

In set-builder form, we use mathematical notation and properties of the elements of the set.

Now,

As per the question;

(a) To represent all the integers congruent to  5 (mod 7) by roaster method of a set A (say):

where

x\in Z such that

x ≡ 5 (mod 7)

Then

A = {... -23, -16, -9, -2, 5, 12, 19, 26, ....}

(b) In set builder form,

A = {x\in Z: x = 5 - 7t,\ t\in Z}

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If z=3 and z*y=12 what does y+5 equal
mart [117]
Z = 3                                              (This equation is a given)

z(y) = 12                                       ( This equation is also given) 

3y = 12                                         (as z = 3, plug 3 into z)

3y/3 = 12/3                                   (isolate the y by dividing 3 to both sides) 
                                                  * you divide 3 to both sides because of the equal                                                             sign. What you do to one side you do to the                                                                    other
y = 4                                             (answer for y)

y + 5                                             (what you are solving for)

(4) + 5 = 9                                    (As y = 4, plug in 4 for y in this equation)

y + 5 = 9                                       (4 + 5 =  9, or addition property)

9 is your answer           

hope this helps
5 0
3 years ago
Find the values of x that satisfy
mr_godi [17]
Setup 2 problems
2x - 7 < 15   and    2x - 7 > -15
2x < 22                  2x > -8
x < 11                    x > -4

Or you can write it  -4 < x < 11

7 0
3 years ago
How do i find LM? On number 2 .
Masja [62]
Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5

Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18

Thus, LM = KL = 18 units.
4 0
4 years ago
What is the answer to number 2 will mark Brainlest!!!!
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6 0
3 years ago
Select all possible values for x if −3x &lt; 15.
makkiz [27]

Step-by-step explanation:

When dividing or multiplying by a negative number, remember to flip the inequality sign.

-3x < 15

x > -5 (divide -3 on both sides, flip the inequality sign)

The correct options are 2 and 9. (D and E)

4 0
3 years ago
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