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3 years ago

8

A high school of 350 students offers biology and chemistry courses. 213 students are enrolled in biology while 155 students are

studying chemistry. 78 students are studying both subjects. how many students are not studying either subject?

1 answer:

NNADVOKAT [17]3 years ago

4 0

350 - 213 - 155 + 78 = 60 students not in either

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Whats the percent difference of 154 and 440

Semmy [17]

This would be a percent increase, so the formula would be:

New amount - Original amount / Original amount

Replace the numbers:

440 - 154 / 440

Simplify.

286 / 440

The chance would be 0.65, or 65%.

7 0

3 years ago

PlES heLP mEh >:D FS:D>FSD:F> SD:F

VashaNatasha [74]

70 I believe is the correct answer

3 0

3 years ago

Read 2 more answers

If you help with the correct answer u are a god .pt2

Brrunno [24]

a. Answer: D: (∞, ∞)

R: (-∞, ∞)

<u>Step-by-step explanation:</u>

Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).

Theoretical range is the range of the equation given the domain.

c(p) = 25p

There are no restrictions on the p so the theoretical domain is All Real Numbers.

Multiplying 25 by All Real Numbers results in the range being All Real Numbers.

a) D: (∞, ∞)

R: (-∞, ∞)

*********************************************************************************

b. Answer: D: (0, 200)

R: (0, 5000)

<u>Step-by-step explanation:</u>

Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.

Practical range is the range of the equation given the practical values of the domain.

The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200

The range is 25p → (25)0 ≤ (25)p ≤ (25)200

→ 0 ≤ 25p ≤ 5000

b) D: (0, 200)

R: (0, 5000)

5 0

3 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

8 0

3 years ago

Describe a real-world situation that the graph could represent. Then describe the possible values for each variable

Alex777 [14]

Answer:

$Speed=distance/time$ i.e. relation between speed-distance-time is one such situation that can be modeled using graph

Step-by-step explanation:

There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.

One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.

So, the equation for speed is represented by equation as follows:

$Speed=distance/time$

So, if we take distance on y axis and time on x axis with points as (distance,time)

(0,0) ==> $v=0/0=0$

(1,2) ==> $v=1/2=0.5$

(2,2) ==> $v=2/2=1$

the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.

8 0

3 years ago