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2 years ago

I just need to state the property and justify with simplify.

Mathematics

1 answer:

kykrilka [37]2 years ago

4 0

Answer:

Step-by-stnxnep explanation:

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If we reject the null hypothesis, does this mean that we have proved it to be false beyond all doubt? Explain your answer.a. Yes

crimeas [40]

Answer:

Yes, the test was conducted with a risk of a type I error.

Step-by-step explanation:

If we reject the null hypothesis, does this mean that we have proved it to be false beyond all doubt? Explain your answer.

Yes, for a null hypothesis to be rejected, it has being proven beyond all doubt that the null hypothesis will not work. the normal distribution has being used for the probability calculation.

if the null hypothesis is rejected and the alternative hypothesis is accepted, a type I error as occur.

In general terms:

‘a hypothesis has been rejected when it should have been accepted’. When this occurs, it is called a type I error.

5 0

2 years ago

On a test that has a normal distribution, a score of 19 falls one standard deviation below the mean, and a score of 40 falls two

nexus9112 [7]

Hi there!

We can use the following equation:

$\large\boxed{z = \frac{x-\mu}{\sigma}}$

z = amount of standard deviations away a value is from the mean (z-score)

σ = standard deviation

x = value

μ = mean

Plug in the knowns for both and rearrange to solve for the mean:

$-1 = \frac{19-\mu}{\sigma}\\\\-\sigma = 19 - \mu\\\\ \sigma = -19 + \mu$

Other given:

$2 = \frac{40-\mu}{\sigma}\\\\2\sigma = 40- \mu\\\\ \sigma = 20 - \frac{\mu}{2}$

Set both equal to each other and solve:

$-19 + \mu = 20 - \frac{\mu}{2}\\\\\frac{3\mu}{2} = 39 \\\\3\mu = 78 \\\\\boxed{\mu = 26 }$

5 0

1 year ago

Help plssss idk what to do!!!!!!!!!

Firdavs [7]

9514 1404 393

Answer:

y = 1

Step-by-step explanation:

Recognize that 25 and 125 are powers of 5 and rewrite the equation in terms of powers of 5.

The applicable rules of exponents are ...

(a^b)^c = a^(bc)

(a^b)/(a^c) = a^(b-c)

(a^b)(a^c) = a^(b+c)

Your equation can be written as ...

$25^4\div5^{5y}=125^y\\\\(5^2)^4\div5^{5y}=(5^3)^y\\\\5^{8-5y}=5^{3y}\\\\8-5y=3y\qquad\text{equate exponents of the same base}$

Now this can be solved as an ordinary linear equation.

8 = 8y . . . . . . add 5y to both sides

1 = y . . . . . . . divide by 8

The solution is y = 1.

4 0

2 years ago

Solve the system using substitution. Write the solution as an ordered pair. (1 point) SHOW YOUR WORK FOR FULL CREDIT! (2 points)

beks73 [17]

x = -2

y = 7

Solution: (-2,7)

//Hope this helps.

3 0

2 years ago

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Which Equation represents the line passing through points a and C on the graph below

zimovet [89]

Answer:

D!!

Step-by-step explanation:

6 0

2 years ago

I just need to state the property and justify with simplify.​

I just need to state the property and justify with simplify.