Someone help meee.....

Gnesinka [82]

A.
the y intercept is where x=0
x represents the number of months
when the number of months is 0, that is the initial number of games won

that looks to be a little below y=2, so maybe y=1.8?
the y intercept is y≈1.8
it represents the number of games won with 0 months of practice

B.
we can use y=mx+b
m=slope
b=y intercept
we know the y intercept
find the slope
slope=rise/run
the I'm going from x=0 to x=10
the rise is about 18.95 (from 1.8 to 20.75)
the run is 10
so slope would be 18.95/10=1.895

the equation would be y=1.895x+1.8
the points were (0,1.8) and (10,20.75)

6 0

3 years ago

Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?

Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the expression,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between M(2, -3) and N(3, 1) will be,

MN = $\sqrt{(3-2)^2+(1+3)^2}$

= $\sqrt{1+16}$

= $\sqrt{17}$

Distance between M(2, -3) and O(-3, 1),

MO = $\sqrt{(2+3)^2+(-3-1)^2}$

= $\sqrt{25+16}$

= $\sqrt{41}$

Distance between N(3, 1) and O(-3, 1),

NO = $\sqrt{(3+3)^2+(1-1)^2}$

= 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

$(\sqrt{41})^2=(\sqrt{17})^2+6^2$

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0

3 years ago

Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the

Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find - What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are - 1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0

3 years ago

Bobby thinks 5^2=10 what is wrong with this answer

nignag [31]

Answer:

5^2 means 5*5 not 5*2

Step-by-step explanation:

5 0

3 years ago

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I NEED SERIOUS HELP PLEASE WITH PROBABILITY

erastova [34]

Since its a six sided die the probability for rolling a single number ( like six or four) is always going to be 1/6.

and since the dice has the numbers 1, 2, 3, 4, 5 and 6 on it the probability for the even and the odd numbers are the same the even being 2, 4, 6 and odd being 1, 3, 5. the probability is 3/6 or simplified 1/2.

3 0

3 years ago

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