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mr_godi [17]
1 year ago
11

Suppose a baker claims that his bread height is more than 15 cm, on average. Several of his

Mathematics
1 answer:
yKpoI14uk [10]1 year ago
4 0
  1. Since the p-value is approximately equal to zero (0), we can conclude that there is sufficient evidence that the true mean height for the baker's loaves of bread is greater than (>) 15 cm.
  2. Since 2.37 is greater than (>) 1.645, we reject the null hypothesis (H₀) at 5% level of significance. Therefore, we can conclude that the company’s claims are invalid.

<h3>What is a null hypothesis?</h3>

A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.

For the baker's claim, the appropriate null and alternative hypotheses would be given by:

H₀: μ ≤ 15

H₁: μ > 15

Since the standard deviation for the height is given, the population would have a normal distribution, and the population standard deviation is given by:

Population standard deviation = σ/√n

Population standard deviation = 0.5/√10

Population standard deviation = 0.16.

For the p-value, we have:

The p-value is the probability that a sample mean would be the same or greater than (≥) 17 cm. Thus, the p-value is given by:

p-value = P(x > 17) ≈ 0.

Since the p-value is approximately equal to zero (0), we can conclude that there is sufficient evidence that the true mean height for the baker's loaves of bread is greater than (>) 15 cm.

Question 3.

For the oil company's claim, the appropriate null and alternative hypotheses would be given by:

H₀: μ = 0.15

H₁: μ > 0.15

<h3>How to calculate value of the z-score?</h3>

The z-score can be calculated by using this formula:

z=\frac{x\;-\;u}{\frac{\sigma}{\sqrt{n} } }

<u>Where:</u>

  • x is the sample mean.
  • u is the mean.
  • is the standard deviation.
  • n is the number of boys.

Substituting the given parameters into the formula, we have;

z=\frac{0.162\;-\;0.15}{\frac{0.04}{\sqrt{40} } }\\\\z=\frac{0.012}{\frac{0.4}{6.3246 } }

z = 0.012/0.0633

z = 0.190.

From the z-table, a z-score of 0.190 is equal to a p-value of 2.37.

For the critical value, we have:

Critical probability (p*) = 1 - α/2

Critical probability (p*) = 1 - 0.1/2

Critical probability (p*) = 0.95.

Hence, the critical value is Zα/2 equal to 1.645.

Since 2.37 is greater than (>) 1.645, we reject the null hypothesis (H₀) at 5% level of significance. Therefore, we can conclude that the company’s claims are invalid.

Read more on null hypothesis here: brainly.com/question/14913351

#SPJ1

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