Using the five-digit system, determine the obstetric history in this situation: the client is 38 weeks into her fourth pregnancy
. her third pregnancy, a twin gestation, ended at 32 weeks with a live birth, her second pregnancy ended at 38 weeks with a live birth, and her first pregnancy ended at 18 weeks.
The answer is G4, T1, P1, A1, L3 Gravida (the first number) is 4 because this woman is now pregnant and was pregnant three times before. Para (the next four numbers) represents the outcomes of the pregnancies and would be described as: T: 1 = Term birth P: 1= Preterm birth A: 1 = Abortion: L: 3= Living children
The five digit system consists of the gravidity (G), term births (T), preterm births (P), abortions (A), and living children (L). The gravidity is the number of times that the patient has been pregnant, regardless of the outcome. For this patient, the number is 4. Term births are babies delivered at 37 weeks AOG or above. For this patient, the number is 1. Preterm births are babies delivered less than 37 weeks AOG and for this patient, the number is 1. Abortions are termination of pregnancy before 20 weeks AOG and for this patient, the number is 1. The number of living children is self explanatory and for this patient, the number is 3.
The five digit score of this patient is G4-T1-P1-A1-L3 or simply 4-1-1-1-3.
It follows that the carnivores (secondary consumers) that feed on herbivores and detritivores and those that eat other carnivores (tertiary consumers) have the lowest amount of energy available to them.
