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taurus [48]
3 years ago
5

Really need some help

Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0
The outer exponent is 4 so there will be 5 terms all together. By rules of exponents

C(4,0)(3^4)(2^0)(x^8)(y^0) + C(4,1)(3^3)(2^1)(x^6)(y^3) + C(4,2)(3^2)(2^2)(x^4)(y^6) + C(4,3)(3^1)(2^3)(x^2)(y^9) + C(4,4)(3^0)(2^4)(x^0)(y^12)


The coefficient of the 3rd term: C(4,2)(3^2)(2^2) = 6 x 9 x 4 = 216
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What is the product? (4y - 3) (2y^2 +3y - 5)
igomit [66]

(4y-3)(2y²+3y-5)

First , let's start with "4y"

4y*2y² = 8y³

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Next, let's multiply by "-3"

-3*2y² = -6y²

-3*3y = -9y

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Now, let's combine all of our values.

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3 years ago
How do I find slope intercept ​
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slamgirl [31]

The regression equation of Y on X is given by the following formula:

Y-\bar{Y}=b_{yx}(X-\bar{X})

Where byx is given by the formula:

b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}

Now, the average of X and Y is the sum divided by N, then:

\begin{gathered} \bar{X}=\frac{167}{8}=20.87 \\ \bar{Y}=\frac{995}{8}=124.37 \end{gathered}

Replace these values in the formula and find the regression equation as follows:

\begin{gathered} Y-124.37=4.6(X-20.87) \\ Y-124.37=4.6X-4.6\cdot20.87 \\ Y=4.6X-96.11+124.37 \\ Y=4.6X+28.26 \end{gathered}

The answer is a) y=4.6x+28.26

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