Answer:
im not sure of the answer
Step-by-step explanation:
Answer:
The standard normal distribution should be used due to the large sample size ; also also proportions are what is required.
Step-by-step explanation:
Given that:
Sample size, n = 1700
p = 63% = 0.63
Given that the sample size is large at n = 1700 ; the binomial distribution and t - distribution aren't ideal for distributions of such size. Also, we are interested in the population proportion which from the standard normal formula who's interval could be obtained thus :
[p ± Zα/2 * sqrt(p(1 - p))]
Both the t-distributon and binomial distributions are for experiments whith relatively small or low.
10 ≥ 2(2.99) + 0.67b
10 ≥ 5.98 + 0.67b
4.02 ≥ 0.67b
6 ≥ b
David can buy 6 pounds of bananas at most.
To increase by 2% you multiply to get 1102*0.02=22.04. You then add that to 1102, getting 1124.04. To then decrease it by 1% you multiply to get 1124.04*0.01=11.24. Subtract 11.24 from 1124.04 to get a final answer of 1112.8