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Sindrei [870]
3 years ago
15

Y-(-4)=-3[x-(2)] I'm looking for the slope intercept form of y

Mathematics
1 answer:
skad [1K]3 years ago
8 0
Y+4=-3(x-2)
y+4=-3x+6
y=-3x+2 and slope is -3
You might be interested in
Jada and Diego are practicing the piano for an upcoming rehearsal. The number of minutes Jada practiced is listed below:
katen-ka-za [31]

Answer:

20

Step-by-step explanation:

First, rewrite the numbers in numerical order:

8, 10, 10, 15, 15, 20, 20, 20, 20, 25, 25, 25, 35

Then find the middle number: (note there's 6 numbers on each side of <u>20</u>)

<em>8 10 10 15 15 20 </em><u>20</u> <em>20 20 25 25 25 35</em>

Hope this helps!

7 0
3 years ago
the trucking company also needs to deliver 1 2/3 tons of oak logs and 1 7/12 tons of maple logs. Which load weighs more?
bekas [8.4K]
Oak logs
1 2/3= 20/12
1 7/12= 19/12
5 0
3 years ago
Which of the following are geometric sequences?<br> Check all that apply.
kolezko [41]

Answers:

<h2>C & D</h2>

Step-by-step explanation:

There are two general types of sequences that follow a pattern, geometric and arithmetic. Let's see the difference between the two:

An arithmetic sequence is produced by adding the same number to all the terms in the sequence.

EXAMPLE:

5, 7, 9, 11, 13, 15, 17 (The number 2 is added to all terms)

To figure out if a sequence is arithmetic, subtract the first term from the second, then the second from the third and so on until you have checked all the terms.

7 - 5 = 2

9 - 7 = 2

11 - 9 = 2

13 - 11 = 2

15 - 13 = 2

17 - 15 = 2

All results equal 2, so the sequence is arithmetic

From your list: The following sequences are arithmetic

A. 5, 10, 15, 20, 25 (common difference of 5)

The next type of sequence is the geometric sequence.

A geometric sequence is produced when the all the terms in the sequence are multiplied or divided by the same number.

EXAMPLE:

100, 50, 25 (Each term is divided by 2)

To figure this out, we divide each term in the sequence by the next term.

100 / 50 = 2

50 / 25 = 2

All results are two, so this sequence can be confirmed to be geometric

From your list: The following sequences are geometric

C. 10, 5, 2.5, 1.25, 0.625, 0.3125 (common quotient of 2)

D. -9, -3, -1, -1/3, -1/9, -1/27 (common quotient of -3)

There is one final type of sequence, which has no common difference, sum, quotient, or product.

EXAMPLE:

5, 6, 8, 9, 11, 12, 14, 15

This sequence has a pattern, the differences between the numbers are not common.

6 - 5 = 1

8 - 6 = 2

9 - 8 = 1

11 - 9 = 2

12 - 11 = 1

14 - 12 = 2

15 - 14 = 1

From your list: The following sequences are neither geometric nor arithmetic

B. 1, 1, 2, 3, 5, 8, 13 (No pattern)

I'n always happy to help :)

6 0
3 years ago
The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers
Elis [28]

Answer:

The numbers are 23 and 7  

Step-by-step explanation:

1. Set up the equations

   Let x = the greater number

  and y = the smaller number. Then

(1) x - y = 16

       4y = 4 times the smaller number and

  4y - 5 = 5 less than 4 times the smaller number. Then

(2)     x = 4y - 5

You have a system of two equations:

\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}

2. Solve the equations

\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}

The larger number is 23; the smaller number is 7.

3. Check

\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}

OK.

3 0
3 years ago
Home CoworkHelper
9966 [12]

Answer:

See below.

Step-by-step explanation:

PROBLEM A

The formula for the volume of a cylinder is

V = πr²h, where πr² is the area of the base.

V = area of base x height

  1. Choose any four numbers that are less than 10 for the height.
  2. Then, substitute into the formula and isolate "r". 10 = πr²h
  3. Double "r" to find the diameter.
  4. The area of the base is found (bolded) while you solve πr².

*I will use the calculator button for pi (π)

<u>Cylinder A: </u><u>h = 1</u>

10 = πr²h

10 = πr²(1)

10 = πr²                       Area of the base is 10m².

r = √ (10/π)

r = 1.78                        Radius is 1.78m.

d = 2r = 1.78*2 = 3.56                     Diameter is 3.56m.

<u>Cylinder B: </u><u>h = 2</u>

10 = πr²h

10 = πr²(2)

5 = πr²                       Area of the base is 5m².

r = √ (5/π)

r = 1.26                      Radius is 1.26m.

d = 2r = 1.26*2 = 2.52                     Diameter is 2.52m.

<u>Cylinder C: </u><u>h = 4</u>

10 = πr²h

10 = πr²(4)

2.5 = πr²                       Area of the base is 2.5m².

r = √ (2.5/π)

r = 0.89                        Radius is 0.89m.

d = 2r = 0.89*2 = 1.78                     Diameter is 1.78m.

<u>Cylinder D: </u><u>h = 5</u>

10 = πr²h

10 = πr²(5)

2 = πr²                       Area of the base is 2m².

r = √ (2/π)

r = 0.80                     Radius is 0.8m.

d = 2r = 0.80*2 = 1.6                     Diameter is 1.6m.

The answers are reasonable if the answer is close to 10 when you substitute the rounded numbers back into the formula and solve.

There are infinite possibilities because any numbers when used in the formula equates to 10 are possible. The height/radius can be any decimal number, which would make the other dimensions change.

PROBLEM B

Follow similar steps if you know the diameter of a cylinder. Use the same formula V = πr²h.

We need the radius, which is half the diameter. r = d/2 = 10/2 = 5

  1. Choose a random number for volume that divides easily by 25.
  2. Substitute "V" and "r²" (r² = 25).
  3. Isolate "h".
  4. The area of the base is 78.54 cm² every time (A = πr²).

<u>Cylinder A: </u><u>V = 100</u>

100 = π25h

4 = πh

h = 1.27                      The height is 1.27m.

<u>Cylinder B: </u><u>V = 200</u>

200 = π25h

8 = πh

h = 2.55                      The height is 2.55m.

<u>Cylinder C: </u><u>V = 75</u>

75 = π25h

3 = πh

h = 0.95                      The height is 0.95m.

<u>Cylinder D: </u><u>V = 125</u>

125 = π25h

5 = πh

h = 1.59                      The height is 1.59m.

The answers are reasonable if I can substitute two rounded values into the formula and get a number close to the third. The height is also a decimal number which occurs because of pi.

6 0
3 years ago
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