<span>A = P(1+r/2)^2t
A/P = (1+r/2)^2t
ln(A/P) = 2t ln((1+r/2))
ln(A/P)/ln(1+r/2) =2t
ln(9000/4190.51)/ln(1+0.052/2)=2t
t=15 yrs
therfore ans is C.14 years ,11 months</span>
Answer: 2,243.4
Step-by-step explanation:
Answer: −10
Step-by-step explanation: 9^2−21/−6
81−21/−6
60/−6
−10
If 1 uniform costs $ 20....and there are 14 players....then Fritz would spend
(20 x 14) = $ 280.....thats if each player only gets 1 uniform .
The events A and B are independent if the probability that event A occurs does not affect the probability that event B occurs.
A and B are independent if the equation P(A∩B) = P(A) P(B) holds true.
P(A∩B) is the probability that both event A and B occur.
Conditional probability is the probability of an event given that some other event first occurs.
P(B|A)=P(A∩B)/P(A)
In the case where events<span> A and B are </span>independent<span> the </span>conditional probability<span> of </span>event<span> B given </span>event<span> A is simply the </span>probability<span> of </span>event<span> B, that is P(B).</span>
Statement 1:A and B are independent events because P(A∣B) = P(A) = 0.12. This is true.
Statement 2:<span>A and B are independent events because P(A∣B) = P(A) = 0.25.
This is true.
Statement 3:</span><span>A and B are not independent events because P(A∣B) = 0.12 and P(A) = 0.25.
This is true.
Statement 4:</span><span>A and B are not independent events because P(A∣B) = 0.375 and P(A) = 0.25
This is true.</span>
