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algol13
2 years ago
15

HELPP I GIVE BRAINLESTT RN I NEED THIS IN 5 MINUTESSS RNNNN

Mathematics
1 answer:
Zepler [3.9K]2 years ago
3 0

thirty-seven point five percent and three per eight

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Consider the equations y = √x and y = x^2 - 1
lord [1]
<h3>Answer:</h3>

(x, y) ≈ (1.49021612010, 1.22074408461)

<h3>Explanation:</h3>

This is best solved graphically or by some other machine method. The approximate solution (x=1.49, y=1.221) can be iterated by any of several approaches to refine the values to the ones given above. The values above were obtained using Newton's method iteration.

_____

Setting the y-values equal and squaring both sides of the equation gives ...

... √x = x² -1

... x = (x² -1)² = x⁴ -2x² +1 . . . . . square both sides

... x⁴ -2x² -x +1 = 0 . . . . . polynomial equation in standard form.

By Descarte's rule of signs, we know there are two positive real roots to this equation. From the graph, we know the other two roots are complex. The second positive real root is extraneous, corresponding to the negative branch of the square root function.

8 0
3 years ago
The midpoint of CD is M(-1,-2). One endpoint is C (-9,-4). Find the coordinates of the other endpoint D.
yan [13]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&C&(~ -9 &,& -4~) &#10;%  (c,d)&#10;&D&(~ x &,& y~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{x-9}{2}~~,~~\cfrac{y-4}{2} \right)=\stackrel{midpoint~M}{(-1~~,~~-2)}\implies &#10;\begin{cases}&#10;\cfrac{x-9}{2}=-1\\\\&#10;x-9=-2\\&#10;\boxed{x=7}\\&#10;----------\\&#10;\cfrac{y-4}{2}=-2\\\\&#10;y-4=-4\\&#10;\boxed{y=0}&#10;\end{cases}
6 0
3 years ago
Solve for q. <br><br> 16pq^2 =25
Nady [450]

Question:

<em>Solve for q.  </em>

<em>16pq^2 =25</em>

Answer:

<em>16pq^=25</em>

<em>p=25/16q^2</em>

<em>q=0</em>

Hope thisd helps!

8 0
3 years ago
Read 2 more answers
Landon used a semicirce, a rectangle, and a right triangle to form the figure shown.
ankoles [38]
Area of rectangle= base x height
6x4=24

Area of triangle= 0.5 base x height
We have the height but we don’t have the base, to calculate the base we subtract 10-6 which equals to 4
0.5 x 4 x4 =8

Area of a semicircle= o.5 x pi x r^2
We have the diameter and to find the radius we divide it by 2
4/2 = 2
0.5 x pi(or 3.14) x 2^2
=6.28
Total area = 24 + 8+ 6.28 =38.28cm^2


8 0
3 years ago
Read 2 more answers
Could someone help and tell me how you got the answer? Will mark brainlist!
zheka24 [161]
Subtract 2 numbers then subtract it with 180 (sorry if you get it wrong)
8 0
3 years ago
Read 2 more answers
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