The relative frequency of students who are not seniors at this high school will be 82.96%.
<h3>How to find how much percent 'a' is of 'b'?</h3>
Suppose a number is 'a'
Suppose another number is 'b'
We want to know how much percent of 'b' is 'a'.
Then, it is calculated as:
P = a/b × 100
A local high school has 1,203 students with 367 freshmen, 382 sophomores, 249 juniors, and 205 seniors.
Then the relative frequency of students who are not seniors at this high school will be
P = 998/1203 × 100
P = 0.82959 × 100
P = 82.959%
P ≈ 82.96%
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Answer:
y = -2·(1/2)^x
Step-by-step explanation:
The ratio of one table entry to the one before is ...
(-2)/(-4) = 1/2
so this is the <em>growth factor</em>.
The <em>multiplier</em> is the value of y when x=0, which is -2. So, the equation is ...
y = (multiplier)·(growth factor)^x
y = -2·(1/2)^x
_____
This can also be written using a negative exponent:
y = -2·2^(-x)
If you add the 12 tens then the answer is 112.
Hoped I Helped!